Chapter 3 Discrete Random Variables and Probability Distributions Part 3: Some Common Discrete Random Variable Distributions Section 3.4 Discrete Uniform Distribution Section 3.5 Bernoulli trials and Binomial Distribution Others sections will cover more of the common discrete distributions: Geometric, Negative Binomial, Hypergeometric, Poisson 1/19
Show that the sum of any three consecutive integers is divisible by 3. The sum is n + (n+1) + (n+2) . A vampire number is a 2n digit number v that factors as v=xy where x and y are n digit numbers and the digits of v are the union of the digits in x and y in some order.
Jul 27, 2009 · It could well be that one could use this strangeness to do something interesting (particularly if, as Gil suggests, we assume that factoring is in P, at which point in order for the answer to be “No”, all large constructible integers are not only composite, but must be smooth).
Jul 27, 2010 · Consecutive integers are two numbers such that one number is the other plus 1. Let n = the smaller integer. n+1 = the larger integer. If their sum is 35, we need to add them together. So: n + (n+1) = 35
Quadratic Equations. A quadratic equation is one of the form ax 2 + bx + c = 0, where a, b, and c are numbers, and a is not equal to 0.. Factoring. This approach to solving equations is based on the fact that if the product of two quantities is zero, then at least one of the quantities must be zero.
When multiplying a sum of two numbers by a third number, it does not matter whether you find the sum first and then multiply or you first multiply each number to be added and then add the two products: 4×(3+2)=(4×3)+(4×2).
Here we will use algebra to find three consecutive integers whose sum is 291. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 291. Therefore, you can write the equation as follows: (X) + (X + 1) + (X + 2) = 291
3(1) - 5 = -2 (3 times second term minus third term), 3(5) - (-2) = 17 (3 times third term minus fourth term) Fibonacci Sequence. One famous example of a recursively defined sequence is the Fibonacci Sequence. The first two terms of the Fibonacci Sequence are 1 by definition. Every term after that is the sum of the two preceding terms.
With these commands, TO define sequences of variables whose names end in consecutive integers. The syntax is two identifiers that begin with the same root and end with numbers, separated by TO. The syntax X1 TO X5 defines 5 variables, named X1, X2, X3, X4, and X5.